X^2-6x-354=0

Solution for X^2-6x-354=0 equation:

X^2-6X-354=0

a = 1; b = -6; c = -354;
Δ = b2-4ac
Δ = -62-4·1·(-354)
Δ = 1452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1452}=\sqrt{484*3}=\sqrt{484}*\sqrt{3}=22\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22\sqrt{3}}{2*1}=\frac{6-22\sqrt{3}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22\sqrt{3}}{2*1}=\frac{6+22\sqrt{3}}{2}
$